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동적 프로그래밍의 두 가지 접근 방식: Top-Down vs. Bottom-Up동적 프로그래밍을 사용할 때, 두 가지 방식으로 문제를 해결할 수 있다..탑다운(Top-Down): 재귀(Recursion) + 메모이제이션(Memoization)보텀업(Bottom-Up): 반복문(Iteration)1. 탑다운(Top-Down) 방식: 재귀 + 메모이제이션private static int[] memo = new int[100];public static int fibTopDownMemo(int n) { if (n == 0) return 0; if (n == 1) return 1; if (memo[n] != 0) return memo[n]; // 이미 계산된 값이면 반환 memo[n] = f..

1. 중복되는 부분 문제 (Overlapping Subproblems)✅ 개념문제를 해결하는 과정에서 동일한 부분 문제가 반복적으로 등장해야 합니다.이전에 계산한 값을 저장하여 재사용하면 연산을 줄일 수 있어야 합니다.🔹 예제: 피보나치 수열 (Fibonacci Sequence)피보나치 수열을 재귀적으로 구하는 코드를 보면, 같은 값이 반복적으로 계산됩니다.public static int fib(int n) { if (n == 0) return 0; if (n == 1) return 1; return fib(n - 1) + fib(n - 2);}❌ fib(5)를 구할 때 fib(3)이 두 번 계산됨.❌ fib(3)을 계산할 때 fib(2)도 중복 계산됨.✅ 중복된 계산을 저장하여 다시 ..

Problem StatementWrite a method named mergeSort that takes an unsorted integer array as input and returns a new sorted array in ascending order using the Merge Sort algorithm.Function Signaturepublic static int[] mergeSort(int[] array)Input:array: An unsorted integer array.Output:A new sorted array containing all elements from the input array in ascending order. 🔹 InstructionsTo implement merge..

Problem StatementWrite a method named merge that takes two sorted integer arrays as input and returns a new sorted array containing all elements from both input arrays in ascending order.Function Signaturepublic static int[] merge(int[] array1, int[] array2)Input:array1: A sorted integer arrayarray2: A sorted integer arrayOutput:A new sorted integer array containing all elements from array1 and ..

📌 Problem RequirementsConvert a sorted singly linked list into a height-balanced binary search tree (BST).A height-balanced BST is a binary tree in which the depth of the two subtrees of any node never differs by more than one.📌 Constraints & ConditionsBinary Search Tree (BST) Property:For each node, all values in the left subtree must be less than the node’s value.All values in the right subt..

public class HanoiTower { // 재귀 메서드: 하노이의 탑 이동 수행 public static void hanoi(int n, char start, char end, char another) { if (n == 1) { // 종료 조건: 원반이 1개일 때 System.out.println("Move 1 from " + start + " to " + end); return; } hanoi(n - 1, start, another, end); System.out.println("Move " + n + " from " + start + " to " + end); hanoi(n - 1, another, end, start); } public ..

Problem StatementYou are given a list of tasks, each with a priority. Your job is to schedule the tasks in order of highest priority first using a priority queue (heap).The priority queue should be implemented using a min-heap or max-heap.Each task has a name and a priority value (lower number = higher priority).The program should process the tasks in order of priority.Example Input & OutputInpu..

Problem Description:You are given an undirected graph represented by a list of edges. Each edge connects two nodes. Your task is to determine if there exists a path between two given nodes, start and end, using Depth-First Search (DFS).Input:An array of edges, where each edge is a pair of integers [u, v], representing an undirected edge between node u and node v.An integer start, the starting no..

📌 Problem StatementYou are given a list of integers, myList, where some elements may be repeated.Your task is to remove all duplicate elements and return a new list containing only the unique elements.✏️ Method Signature:public static List removeDuplicates(List myList);🔹 Example Input & OutputInput: [1, 2, 2, 3, 4, 4, 5] Output: [1, 2, 3, 4, 5]🛠 Solution ApproachWe can solve this problem ef..

We have two arrays, arr1 = {1, 2, 3} and arr2 = {4, 5, 6}, and we want to check if they have any common elements.1️⃣ Using a for Loop (Brute Force)🔹 Codepublic class ArrayComparison { public static void main(String[] args) { int[] arr1 = {1, 2, 3}; int[] arr2 = {4, 5, 6}; boolean hasCommon = false; // Nested for-loop to compare elements for (int i = 0; i 🔹..